From bcc8a059783c11fa66bd97eea8556df07444d8fb Mon Sep 17 00:00:00 2001
From: Thomas Stibor <thomas@stibor.net>
Date: Mon, 13 Apr 2020 19:21:22 +0200
Subject: [PATCH] Determine correct size of TICKER_CHARACTER_COUNT

Since tickerCharacters is a char pointer rather than a char array the
result is: sizeof(8) / sizeof(1).
However, desired
result is: sizeof(5) / sizeof(1).

See also following example:

const char *tickerCharacters = "|/-\\";
const char _tickerCharacters[] = "|/-\\";

int main(void)
{
	printf("%zu\n", (sizeof(tickerCharacters) / sizeof(char)));
	printf("%zu\n", (sizeof(_tickerCharacters) / sizeof(char)));

	return 0;
}

> gcc test.c -o test && ./test
8
5
---
 src/main/io/dashboard.c | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/src/main/io/dashboard.c b/src/main/io/dashboard.c
index bbb53b3d24..384de9cde3 100644
--- a/src/main/io/dashboard.c
+++ b/src/main/io/dashboard.c
@@ -104,7 +104,7 @@ typedef struct pageEntry_s {
     uint8_t flags;
 } pageEntry_t;
 
-static const char* tickerCharacters = "|/-\\"; // use 2/4/8 characters so that the divide is optimal.
+static const char tickerCharacters[] = "|/-\\"; // use 2/4/8 characters so that the divide is optimal.
 #define TICKER_CHARACTER_COUNT (sizeof(tickerCharacters) / sizeof(char))
 
 typedef enum {