utils: raspberrypi: ctt: Fix NaNs in lens shading tables

The problem occurs when the calculation could lead to a final row (or
column) of grid squares with no pixels in them (and hence, NaNs).

One specific case is a Pi 5 with an image width (or height) of 1364,
so that's 682 Bayer quads. To give 32 grid squares it was calculating
22 quads per cell. However, 31 * 22 = 682 leaving nothing in the final
column.

The fix is to do a rounding-down division by the number of cells minus
one, rather than a rounding-up division by the number of cells. This
turns the corner case from one where the final row/column has no
pixels to one where we don't quite cover the full image, which is how
we have to handle these cases.

Bug: https://github.com/raspberrypi/libcamera/issues/254
Signed-off-by: David Plowman <david.plowman@raspberrypi.com>
Reviewed-by: Naushir Patuck <naush@raspberrypi.com>
Acked-by: Kieran Bingham <kieran.bingham@ideasonboard.com>
Signed-off-by: Kieran Bingham <kieran.bingham@ideasonboard.com>
This commit is contained in:
David Plowman 2025-04-28 11:36:03 +01:00 committed by Kieran Bingham
parent 9b50d3c23d
commit 36ba0e5515

View file

@ -127,11 +127,12 @@ def alsc(Cam, Img, do_alsc_colour, plot=False, grid_size=(16, 12), max_gain=8.0)
channels = [Img.channels[i] for i in Img.order] channels = [Img.channels[i] for i in Img.order]
""" """
calculate size of single rectangle. calculate size of single rectangle.
-(-(w-1)//32) is a ceiling division. w-1 is to deal robustly with the case The divisions here must ensure the final row/column of cells has a non-zero number of
where w is a multiple of 32. pixels.
""" """
w, h = Img.w/2, Img.h/2 w, h = Img.w/2, Img.h/2
dx, dy = int(-(-(w-1)//grid_w)), int(-(-(h-1)//grid_h)) dx, dy = (w - 1) // (grid_w - 1), (h - 1) // (grid_h - 1)
""" """
average the green channels into one average the green channels into one
""" """