libcamera: yaml_parser: Remove memberNames() function
Now that YamlObject supports iteration, the memberNames() function isn't useful anymore as it can be implemented using utils::map_keys() if really needed. Drop it. Signed-off-by: Laurent Pinchart <laurent.pinchart@ideasonboard.com> Reviewed-by: Jacopo Mondi <jacopo@jmondi.org> Reviewed-by: Han-Lin Chen <hanlinchen@chromium.org>
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3 changed files with 0 additions and 33 deletions
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@ -172,7 +172,6 @@ public:
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bool contains(const std::string &key) const;
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bool contains(const std::string &key) const;
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const YamlObject &operator[](const std::string &key) const;
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const YamlObject &operator[](const std::string &key) const;
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std::vector<std::string> memberNames() const;
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private:
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private:
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LIBCAMERA_DISABLE_COPY_AND_MOVE(YamlObject)
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LIBCAMERA_DISABLE_COPY_AND_MOVE(YamlObject)
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@ -335,28 +335,6 @@ bool YamlObject::contains(const std::string &key) const
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return true;
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return true;
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}
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}
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/**
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* \fn YamlObject::memberNames()
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* \brief Retrieve all member names of the dictionary
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*
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* This function retrieve member names of a YamlObject. Only YamlObject
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* instances of Dictionary type associate elements with names, calling this
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* function on other types of instances is invalid and results in undefined
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* behaviour.
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*
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* \todo Replace this function with an iterator-based API
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*
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* \return A vector of string as the member names
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*/
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std::vector<std::string> YamlObject::memberNames() const
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{
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std::vector<std::string> memberNames;
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for (auto &[key, _] : dictionary_)
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memberNames.push_back(key);
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return memberNames;
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}
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/**
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/**
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* \fn YamlObject::operator[](const std::string &key) const
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* \fn YamlObject::operator[](const std::string &key) const
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* \brief Retrieve a member by name from the dictionary
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* \brief Retrieve a member by name from the dictionary
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@ -500,16 +500,6 @@ protected:
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/* Make sure utils::map_keys() works on the adapter. */
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/* Make sure utils::map_keys() works on the adapter. */
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(void)utils::map_keys(dictObj.asDict());
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(void)utils::map_keys(dictObj.asDict());
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auto memeberNames = dictObj.memberNames();
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sort(memeberNames.begin(), memeberNames.end());
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if (memeberNames[0] != "a" ||
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memeberNames[1] != "b" ||
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memeberNames[2] != "c") {
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cerr << "Dictionary object fail to parse member names" << std::endl;
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return TestFail;
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}
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/* Test leveled objects */
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/* Test leveled objects */
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auto &level1Obj = (*root)["level1"];
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auto &level1Obj = (*root)["level1"];
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